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Use Logarithmic Differentiation to Find the Derivative of Y y=xsinxx+1y = \frac { x \sin x } { \sqrt { x + 1 } }

Question 243

Multiple Choice

Use logarithmic differentiation to find the derivative of y.
- y=xsinxx+1y = \frac { x \sin x } { \sqrt { x + 1 } }


A) xsinxx+1(1x+cotx12x+2) \frac { x \sin x } { \sqrt { x + 1 } } \left( \frac { 1 } { x } + \cot x - \frac { 1 } { 2 x + 2 } \right)
B) xsinxx+1lnx+lnsinx12ln(x+1) ) \left. \frac { x \sin x } { \sqrt { x + 1 } } \ln x + \ln \sin x - \frac { 1 } { 2 } \ln ( x + 1 ) \right)
C) 1x+cotx12x+2\frac { 1 } { x } + \cot x - \frac { 1 } { 2 x + 2 }
D) 12(1x+1sinx+1x+1) \frac { 1 } { 2 } \left( \frac { 1 } { x } + \frac { 1 } { \sin x } + \frac { 1 } { x + 1 } \right)

Correct Answer:

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