Use a Reference Triangle in an Appropriate Quadrant to Find $\sec ^ { - 1 } ( \sqrt { 2 } )$

Multiple Choice

Use a reference triangle in an appropriate quadrant to find the angle.
- $\sec ^ { - 1 } ( \sqrt { 2 } )$

A) $\frac { 3 \pi } { 4 }$
B) $\frac { 7 \pi } { 4 }$
C) $\frac { \pi } { 4 }$
D) $\frac { \pi } { 4 } \pm 2 \pi \mathrm { n } , \frac { 7 \pi } { 4 } \pm 2 \pi \mathrm { n }$