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Use the Table of Values of F to Estimate the Limit

Question 169

Multiple Choice

Use the table of values of f to estimate the limit.
-  Let f(x) =x4x2, find limx4f(x) \text { Let } f(x) =\frac{x-4}{\sqrt{x}-2} \text {, find } \lim _{x-4} f(x)
x3.93.993.9994.0014.014.1f(x) \begin{array}{c|l|l|l|l|l|l}\mathrm{x} & 3.9 & 3.99 & 3.999 & 4.001 & 4.01 & 4.1 \\\hline \mathrm{f}(\mathrm{x}) & & & & & &\end{array}


A)
x3.93.993.9994.0014.014.1f(x) 3.974843.997503.999754.000254.002504.02485; limit = 4.0 \begin{array}{c|llllll}\mathrm{x} & 3.9 & 3.99 & 3.999 & 4.001 & 4.01 & 4.1 \\\hline \mathrm{f}(\mathrm{x}) & 3.97484 & 3.99750 & 3.99975 & 4.00025 & 4.00250 & 4.02485\end{array} \text {; limit = 4.0 }

B)
x3.93.993.9994.0014.014.1f(x) 1.192451.199251.199931.200071.200751.20745; limit =1.20\begin{array}{c|llllll}\mathrm{x} & 3.9 & 3.99 & 3.999 & 4.001 & 4.01 & 4.1 \\\hline f(x) & 1.19245 & 1.19925 & 1.19993 & 1.20007 & 1.20075 & 1.20745\end{array} \text {; limit }=1.20

C)
x3.93.993.9994.0014.014.1f(x) 1.192451.199251.199931.200071.200751.20745; limit =\begin{array}{c|llllll}\mathrm{x} & 3.9 & 3.99 & 3.999 & 4.001 & 4.01 & 4.1 \\\hline \mathrm{f}(\mathrm{x}) & 1.19245 & 1.19925 & 1.19993 & 1.20007 & 1.20075 & 1.20745\end{array} ; \text { limit }=\infty

D)
x3.93.993.9994.0014.014.1f(x) 5.077365.097755.099785.100225.102255.12236 limit = 5.10 \begin{array}{c|llllll}\mathrm{x} & 3.9 & 3.99 & 3.999 & 4.001 & 4.01 & 4.1 \\\hline \mathrm{f}(\mathrm{x}) & 5.07736 & 5.09775 & 5.09978 & 5.10022 & 5.10225 & 5.12236\end{array} \text { limit = 5.10 }

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