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 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }

Question 222

Multiple Choice

 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }
- limx0sinxcos4xx+xcos5x\lim _ { x \rightarrow 0 } \frac { \sin x \cos 4 x } { x + x \cos 5 x }


A) 12\frac { 1 } { 2 }
B) does not exist
C) 45\frac { 4 } { 5 }
D) 0

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