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 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }

Question 76

Multiple Choice

 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }
- limx0x22x+sinxx\lim _ { x \rightarrow 0 } \frac { x ^ { 2 } - 2 x + \sin x } { x }


A) -1
B) 1
C) does not exist
D) 0

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