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Find the Intervals on Which the Function Is Continuous y=sin(3θ)5θy = \frac { \sin ( 3 \theta ) } { 5 \theta }

Question 107

Multiple Choice

Find the intervals on which the function is continuous.
- y=sin(3θ) 5θy = \frac { \sin ( 3 \theta ) } { 5 \theta }


A) discontinuous only when θ=π\theta = \pi
B) discontinuous only when θ=0\theta = 0
C) continuous everywhere
D) discontinuous only when θ=π2\theta = \frac { \pi } { 2 }

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