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  2. Topic
    Mathematics
  3. Study Set
    Thomas Calculus Early Transcendentals
  4. Exam
    Exam 15: Partial Derivatives
  5. Question
    Sketch the Surface Z = F(x,y)\(f ( x , y ) = 1 - | x |\)
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Sketch the Surface Z = F(x,y) f(x,y)=1−∣x∣f ( x , y ) = 1 - | x |f(x,y)=1−∣x∣

Question 42

Question 42

Multiple Choice

Sketch the surface z = f(x,y) .
- f(x,y) =1−∣x∣f ( x , y ) = 1 - | x |f(x,y) =1−∣x∣


A)
 Sketch the surface z = f(x,y) . - f ( x , y )  = 1 - | x |   A)    B)    C)    D)
B)
 Sketch the surface z = f(x,y) . - f ( x , y )  = 1 - | x |   A)    B)    C)    D)
C)
 Sketch the surface z = f(x,y) . - f ( x , y )  = 1 - | x |   A)    B)    C)    D)
D)
 Sketch the surface z = f(x,y) . - f ( x , y )  = 1 - | x |   A)    B)    C)    D)

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