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Solve the Problem a=6955 kma = 6955 \mathrm {~km} Calculate the Period of the Satellite

Question 111

Multiple Choice

Solve the problem.
-The orbit of a satellite had a semimajor axis of a=6955 kma = 6955 \mathrm {~km} . Calculate the period of the satellite. (Earth's mass =5.975×1024 kg= 5.975 \times 10 ^ { 24 } \mathrm {~kg} and G=6.6720×1011Nm2 kg2\mathrm { G } = 6.6720 \times 10 ^ { - 11 } \mathrm { Nm } ^ { 2 } \mathrm {~kg} - 2 ) .


A) 0.18 sec
B) 96.2 min
C) 124 min
D) 9250 hr

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