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The Eccentricity Is Given of a Conic Section with One r=451+5cosθr = \frac { 45 } { 1 + 5 \cos \theta }

Question 221

Multiple Choice

The eccentricity is given of a conic section with one focus at the origin, along with the directrix corresponding to that focus. Find a polar equation for the conic section.
-e = 5, y = 9


A) r=451+5cosθr = \frac { 45 } { 1 + 5 \cos \theta }
B) r=4515sinθr = \frac { 45 } { 1 - 5 \sin \theta }
C) r=451+5sinθr = \frac { 45 } { 1 + 5 \sin \theta }
D) r=451+9sinθr = \frac { 45 } { 1 + 9 \sin \theta }

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