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The Eccentricity Is Given of a Conic Section with One r=1612cosθr = \frac { 16 } { 1 - 2 \cos \theta }

Question 150

Multiple Choice

The eccentricity is given of a conic section with one focus at the origin, along with the directrix corresponding to that focus. Find a polar equation for the conic section.
-e = 2, x = -8


A) r=1612cosθr = \frac { 16 } { 1 - 2 \cos \theta }
B) r=161+2cosθr = \frac { 16 } { 1 + 2 \cos \theta }
C) r=161+8cosθr = \frac { 16 } { 1 + 8 \cos \theta }
D) r=1612sinθr = \frac { 16 } { 1 - 2 \sin \theta }

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