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Solve for the Angle , Where 0 2
- sin2θ=34\sin ^ { 2 } \theta = \frac { 3 } { 4 }

Question 129

Multiple Choice

Solve for the angle , where 0 2
- sin2θ=34\sin ^ { 2 } \theta = \frac { 3 } { 4 }


A) θ=0,π,2π\theta = 0 , \pi , 2 \pi
B) θ=π3,2π3,4π3,5π3\theta = \frac { \pi } { 3 } , \frac { 2 \pi } { 3 } , \frac { 4 \pi } { 3 } , \frac { 5 \pi } { 3 }
C) θ=π6,5π6,7π6,11π6\theta = \frac { \pi } { 6 } , \frac { 5 \pi } { 6 } , \frac { 7 \pi } { 6 } , \frac { 11 \pi } { 6 }
D) θ=π4,3π4,5π4,7π4\theta = \frac { \pi } { 4 } , \frac { 3 \pi } { 4 } , \frac { 5 \pi } { 4 } , \frac { 7 \pi } { 4 }

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