Determine from Its Graph If the Function Is One-To-One$$f ( x ) = \left\{ \begin{array} { l l }
x + 5 , & x 0 \
4 , & x \leq 0
\end{array} \right.$$

Question

Determine from Its Graph If the Function Is One-To-One$$f ( x ) = \left\{ \begin{array} { l l } 
x + 5 , & x > 0 \
4 , & x \leq 0
\end{array} \right.$$

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The Answer of Determine from Its Graph If the Function Is One-To-One$$f ( x ) = \left\{ \begin{array} { l l } 
x + 5 , & x > 0 \
4 , & x \leq 0
\end{array} \right.$$

Determine from Its Graph If the Function Is One-To-One $f ( x ) = \left\{ \begin{array} { l l } x + 5 , & x > 0 \\4 , & x \leq 0\end{array} \right.$

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Determine from Its Graph If the Function Is One-To-One f(x)={x+5,x>04,x≤0f ( x ) = \left\{ \begin{array} { l l } x + 5 , & x > 0 \\4 , & x \leq 0\end{array} \right.f(x)={x+5,4,​x>0x≤0​

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Determine from Its Graph If the Function Is One-To-One $f ( x ) = \left\{ \begin{array} { l l } x + 5 , & x > 0 \\4 , & x \leq 0\end{array} \right.$

Correct Answer:
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