Determine from Its Graph If the Function Is One-To-One$$f ( x ) = \left\{ \begin{array} { l l }
1 + \frac { x } { 5 } , & x \geq 0 \
\frac { x } { x - 5 } , & x

Question

Determine from Its Graph If the Function Is One-To-One$$f ( x ) = \left\{ \begin{array} { l l } 
1 + \frac { x } { 5 } , & x \geq 0 \
\frac { x } { x - 5 } , & x < 0
\end{array} \right.$$

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The Answer of Determine from Its Graph If the Function Is One-To-One$$f ( x ) = \left\{ \begin{array} { l l } 
1 + \frac { x } { 5 } , & x \geq 0 \
\frac { x } { x - 5 } , & x < 0
\end{array} \right.$$

Determine from Its Graph If the Function Is One-To-One $f ( x ) = \left\{ \begin{array} { l l } 1 + \frac { x } { 5 } , & x \geq 0 \\\frac { x } { x - 5 } , & x < 0\end{array} \right.$

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Determine from Its Graph If the Function Is One-To-One f(x)={1+x5,x≥0xx−5,x<0f ( x ) = \left\{ \begin{array} { l l } 1 + \frac { x } { 5 } , & x \geq 0 \\\frac { x } { x - 5 } , & x < 0\end{array} \right.f(x)={1+5x​,x−5x​,​x≥0x<0​

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Determine from Its Graph If the Function Is One-To-One $f ( x ) = \left\{ \begin{array} { l l } 1 + \frac { x } { 5 } , & x \geq 0 \\\frac { x } { x - 5 } , & x < 0\end{array} \right.$

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