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Graph Ellipses Not Centered at the Origin
- $\frac { ( x + 2 ) ^ { 2 } } { 16 } + \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1$

Question 106

Multiple Choice

Graph Ellipses Not Centered at the Origin
- $\frac { ( x + 2 ) ^ { 2 } } { 16 } + \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1$
$Graph Ellipses Not Centered at the Origin - \frac { ( x + 2 ) ^ { 2 } } { 16 } + \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1 A) B) C) D)$

A)
$Graph Ellipses Not Centered at the Origin - \frac { ( x + 2 ) ^ { 2 } } { 16 } + \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1 A) B) C) D)$
B)
$Graph Ellipses Not Centered at the Origin - \frac { ( x + 2 ) ^ { 2 } } { 16 } + \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1 A) B) C) D)$
C)
$Graph Ellipses Not Centered at the Origin - \frac { ( x + 2 ) ^ { 2 } } { 16 } + \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1 A) B) C) D)$
D)
$Graph Ellipses Not Centered at the Origin - \frac { ( x + 2 ) ^ { 2 } } { 16 } + \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1 A) B) C) D)$

Graph Ellipses Not Centered at the Origin - (x+2)216+(y+1)24=1\frac { ( x + 2 ) ^ { 2 } } { 16 } + \frac { ( y + 1 ) ^ { 2 } } { 4 } = 116(x+2)2​+4(y+1)2​=1

Multiple Choice

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Graph Ellipses Not Centered at the Origin
- $\frac { ( x + 2 ) ^ { 2 } } { 16 } + \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1$

Correct Answer:
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