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Model Applied Situations with Matrix Operations
The \perp Shape in the Figure Below Is Shown Using 9 Pixels

Question 117

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Model Applied Situations with Matrix Operations
The \perp shape in the figure below is shown using 9 pixels in a 3×33 \times 3 grid. The color levels are given to the right of the figure. Use the matrix [131131333]\left[ \begin{array} { l l l } 1 & 3 & 1 \\ 1 & 3 & 1 \\ 3 & 3 & 3 \end{array} \right] that represents a digital photograph of the \perp shape to solve the problem.  Model Applied Situations with Matrix Operations  The  \perp  shape in the figure below is shown using 9 pixels in a  3 \times 3  grid. The color levels are given to the right of the figure. Use the matrix  \left[ \begin{array} { l l l } 1 & 3 & 1 \\ 1 & 3 & 1 \\ 3 & 3 & 3 \end{array} \right]  that represents a digital photograph of the  \perp  shape to solve the problem.   -Using the same color levels from the instructions, write a 3 × 3 matrix A that represents the letter L in dark grey on a white background. Then find a 3 × 3 matrix B so that A + B lightens only the letter L from dark Grey to light grey.  A)   A = \left[ \begin{array} { l l l } 2 & 0 & 0 \\ 2 & 0 & 0 \\ 2 & 2 & 2 \end{array} \right] ; B = \left[ \begin{array} { r r r } - 1 & 0 & 0 \\ - 1 & 0 & 0 \\ - 1 & - 1 & - 1 \end{array} \right]  B)   A = \left[ \begin{array} { l l l } 2 & 1 & 1 \\ 2 & 1 & 1 \\ 2 & 2 & 2 \end{array} \right] ; B = \left[ \begin{array} { l l l } 1 & 0 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \end{array} \right]  C)   A = \left[ \begin{array} { l l l } 1 & 0 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \end{array} \right] ; B = \left[ \begin{array} { r r r } - 1 & 0 & 0 \\ - 1 & 0 & 0 \\ - 1 & - 1 & - 1 \end{array} \right]  D)   A = \left[ \begin{array} { l l l }  3 & 1 & 1 \\ 3 & 1 & 1 \\ 3 & 3 & 3 \end{array} \right] ; B = \left[ \begin{array} { l l l }  - 2 & - 1 & - 1 \\ - 2 & - 1 & - 1 \\ - 2 & - 2 & - 2 \end{array} \right]
-Using the same color levels from the instructions, write a 3 × 3 matrix A that represents the letter L in dark grey on a white background. Then find a 3 × 3 matrix B so that A + B lightens only the letter L from dark
Grey to light grey.


A)
A=[200200222];B=[100100111]A = \left[ \begin{array} { l l l } 2 & 0 & 0 \\ 2 & 0 & 0 \\ 2 & 2 & 2 \end{array} \right] ; B = \left[ \begin{array} { r r r } - 1 & 0 & 0 \\ - 1 & 0 & 0 \\ - 1 & - 1 & - 1 \end{array} \right]
B)
A=[211211222];B=[100100111]A = \left[ \begin{array} { l l l } 2 & 1 & 1 \\ 2 & 1 & 1 \\ 2 & 2 & 2 \end{array} \right] ; B = \left[ \begin{array} { l l l } 1 & 0 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \end{array} \right]
C)
A=[100100111];B=[100100111]A = \left[ \begin{array} { l l l } 1 & 0 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \end{array} \right] ; B = \left[ \begin{array} { r r r } - 1 & 0 & 0 \\ - 1 & 0 & 0 \\ - 1 & - 1 & - 1 \end{array} \right]
D)
A=[311311333];B=[211211222]A = \left[ \begin{array} { l l l } 3 & 1 & 1 \\3 & 1 & 1 \\3 & 3 & 3\end{array} \right] ; B = \left[ \begin{array} { l l l } - 2 & - 1 & - 1 \\- 2 & - 1 & - 1 \\- 2 & - 2 & - 2\end{array} \right]

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