Solve the Problem $y = - \frac { 1 } { 3000 } x - 6900$

Multiple Choice

Solve the problem.

-The average value of a certain type of automobile was $15,900 in 1991 and depreciated to $6900 in 1994. Let y be the average value of the automobile in the year x, where x = 0 represents 1991.
Write a linear equation that models the value of the automobile (y) in terms of the year x.

A) $y = - \frac { 1 } { 3000 } x - 6900$
B) $y = - 3000 x + 6900$
C) $\mathrm { y } = - 3000 \mathrm { x } + 15,900$
D) $y = - 3000 x - 2100$