Solve the Problem $y = \frac { 1 } { 435 } x + 3654$

Multiple Choice

Solve the problem.

-An investment is worth $3654 in 1993. By 1997 it has grown to $5394. Let y be the value of the investment in the year x, where x = 0 represents 1993. Write a linear equation that models the
Value of the investment (y) in the year x.

A) $y = \frac { 1 } { 435 } x + 3654$
B) $y = - 435 x + 7134$
C) $y = - 435 x + 3654$
D) $y = 435 x + 3654$