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-A Person at the Top of a 600 Foot h=16t2+600h = - 16 t ^ { 2 } + 600

Question 6

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-A person at the top of a 600 foot tall building drops a yellow ball. The height of the yellow ball is given by the equation h=16t2+600h = - 16 t ^ { 2 } + 600 where hh is measured in feet and tt is the number of seconds since the yellow ball was dropped. A second person, in the same building but on a lower floor that is 348 feet from the ground, drops a white ball 3.53.5 seconds after the yellow ball was dropped. The height of the white ball is given by the equation h=16(t3.5) 2+348h = - 16 ( t - 3.5 ) ^ { 2 } + 348 where hh is measured in feet and tt is the number of seconds since the yellow ball was dropped. Find the time that the balls are the same distance above the ground and find this distance.


A) 3sec;456ft3 \mathrm { sec } ; 456 \mathrm { ft }
B) 4sec;344ft4 \mathrm { sec } ; 344 \mathrm { ft }
C) 3.5sec;404ft3.5 \mathrm { sec } ; 404 \mathrm { ft }
D) 4.5sec;276ft4.5 \mathrm { sec } ; 276 \mathrm { ft }

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