Solve the Problem $$f ( x ) = ( x - 10 ) ^ { 2 } + 2 ( x \geq 10 )$$

Multiple Choice

Solve the problem.
- $$f ( x ) = ( x - 10 ) ^ { 2 } + 2 ( x \geq 10 )$$

A) $f ^ { - 1 } ( x ) = \sqrt { x + 10 } - 2 , x \geq - 10$
B) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \sqrt { \mathrm { x } + 2 } - 10 , \mathrm { x } \geq - 2$
C) $f ^ { - 1 } ( x ) = 2 x ^ { 2 } + 10 , x \geq 0$
D) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \sqrt { \mathrm { x } - 2 } + 10 , \mathrm { x } \geq 2$