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Solve the Problem f(x)=x3x+2f ( x ) = \frac { x - 3 } { x + 2 }

Question 5

Multiple Choice

Solve the problem.
-Given f(x) =x3x+2f ( x ) = \frac { x - 3 } { x + 2 } , find all values for xx for which f(x) >0f ( x ) > 0 .


A) (2,3) ( - 2,3 )
B) (3,) ( 3 , \infty )
C) (,2) (3,) ( - \infty , - 2 ) \cup ( 3 , \infty )
D) (,2) ( - \infty , - 2 )

Correct Answer:

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