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The Following MINITAB Output Display Presents the Results of a Hypothesis

Question 13

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The following MINITAB output display presents the results of a hypothesis test for the difference μ1μ2\mu _ { 1 } - \mu _ { 2 } between two population means.  Two-sample T for X1 vs X2  A  N  Mean  StDev  SE Mean  B 1360.49226.6897.4021286.83026.3787.615\begin{array}{lrrcc}\hline{\text { Two-sample T for X1 vs X2 }} & & \\\text { A } & \text { N } & \text { Mean } & \text { StDev } & \text { SE Mean } \\\text { B } & 13 & 60.492 & 26.689 & 7.402 \\& 12 & 86.830 & 26.378 & 7.615\end{array}
Difference =mu(X1)mu(X2) =m u(X 1)-m u(X 2)
Estimate for difference: 26.338 -26.338
95% 95 \% CI for difference: (47.152,5.524) (-47.152,-5.524)
T-Test of difference =0( =0( vs not =) =) : T-Value =2.480133 =-2.480133
 P-Value =1.979112 DF =23\text { P-Value }=1.979112 \quad \text { DF }=23
 Can you reject H0 rejected at the α=0.10 level? \text { Can you reject } H _ { 0 } \text { rejected at the } \alpha = 0.10 \text { level? }

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