The Probabilities That a Batch of 4 Computers Will Contain $\mu = 0.80$

Multiple Choice

The probabilities that a batch of 4 computers will contain 0, 1, 2, 3, and 4 defective computers are 0.4096, 0.4096, 0.1536, 0.0256, and 0.0016, respectively. Round answer to the nearest hundredth.

A) $\mu = 0.80$
B) $\mu = 1.21$
C) $\mu = 0.70$
D) $\mu = 2.00$