Use the following for questions
An operations manager was interested in determining if there is a relationship between the amount of training received by production line workers and the time it takes for them to troubleshoot a process problem. A sample of recently trained line workers was selected. The number of hours of training time received and the time it took (in minutes) for them to troubleshoot their last process problem were captured. Below are the scatterplot, regression results, and residual plots for these data. The regression equation is
Trouble Shooting

= 30.7 - 1.84

Training

\begin{array} { l r r r r } \text { Predictor } & \text { Coef } & \text { SE Coef } & \text { T } & \text { P } \\ \text { Constant } & 30.729 & 1.023 & 30.03 & 0.000 \\ \text { Training } & - 1.8360 & 0.1376 & - 13.35 & 0.000 \end{array}

S = 1.43588 \quad \mathrm { R } - \mathrm { Sq } = 93.2 \text { \% } \quad \mathrm { R } - \mathrm { Sq } ( \mathrm { adj } ) = 92.7 \text { \% }

Analysis of Variance

\begin{array} { l r r r r r } \text { Source } & \text { DF } & \text { SS } & \text { MS } & \text { F } & \text { P } \\ \text { Regression } & 1 & 367.20 & 367.20 & 178.10 & 0.000 \\ \text { Residual Error } & 13 & 26.80 & 2.06 & & \\ \text { Total } & 14 & 394.00 & & & \end{array}

$Use the following for questions An operations manager was interested in determining if there is a relationship between the amount of training received by production line workers and the time it takes for them to troubleshoot a process problem. A sample of recently trained line workers was selected. The number of hours of training time received and the time it took (in minutes) for them to troubleshoot their last process problem were captured. Below are the scatterplot, regression results, and residual plots for these data. The regression equation is Trouble Shooting = 30.7 - 1.84 Training \begin{array} { l r r r r } \text { Predictor } & \text { Coef } & \text { SE Coef } & \text { T } & \text { P } \\ \text { Constant } & 30.729 & 1.023 & 30.03 & 0.000 \\ \text { Training } & - 1.8360 & 0.1376 & - 13.35 & 0.000 \end{array} S = 1.43588 \quad \mathrm { R } - \mathrm { Sq } = 93.2 \text { \% } \quad \mathrm { R } - \mathrm { Sq } ( \mathrm { adj } ) = 92.7 \text { \% } Analysis of Variance \begin{array} { l r r r r r } \text { Source } & \text { DF } & \text { SS } & \text { MS } & \text { F } & \text { P } \\ \text { Regression } & 1 & 367.20 & 367.20 & 178.10 & 0.000 \\ \text { Residual Error } & 13 & 26.80 & 2.06 & & \\ \text { Total } & 14 & 394.00 & & & \end{array} -According to the data, a worker who received 8 hours of training had a troubleshooting time of 15 minutes. What is the value of the residual for this worker? Explain what the residual means.$

-According to the data, a worker who received 8 hours of training had a
troubleshooting time of 15 minutes. What is the value of the residual for this worker?
Explain what the residual means.

Data on Labor Productivity and Unit Labor Costs Were Obtained

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