Approximately How Much Uranium (In Kg) Must Undergo Fission Per

Multiple Choice

Approximately how much uranium (in kg) must undergo fission per day to provide 1 000 MW of power? (Assume an efficiency of 30%) . The nuclear reaction is . m(n) = 1.008 665 u
M(U) = 235.043 915 u
M(Ba) = 140.913 9 u
M(Kr) = 91.897 3 u
U = 1.66 × 10−²⁷ kg

A) 1.0
B) 3.5
C) 2.3
D) 4.6
E) 0.1