Solved

Potential Energy of a Current Loop: a Round Loop of Diameter

Question 21

Multiple Choice

Potential energy of a current loop: A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field Potential energy of a current loop: A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field = 0.20 T + 0.40 T . The normal to the loop is parallel to the unit vector = -0.60 - 0.80 . What is the potential energy of the loop? A) -4.5 × 10<sup>-3</sup> J B) +2.0 × 10<sup>-3</sup> J C) -2.0 × 10<sup>-3</sup> J D) -2.3 × 10<sup>-3</sup> J E) +4.5 × 10<sup>-3</sup> J = 0.20 T Potential energy of a current loop: A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field = 0.20 T + 0.40 T . The normal to the loop is parallel to the unit vector = -0.60 - 0.80 . What is the potential energy of the loop? A) -4.5 × 10<sup>-3</sup> J B) +2.0 × 10<sup>-3</sup> J C) -2.0 × 10<sup>-3</sup> J D) -2.3 × 10<sup>-3</sup> J E) +4.5 × 10<sup>-3</sup> J + 0.40 T Potential energy of a current loop: A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field = 0.20 T + 0.40 T . The normal to the loop is parallel to the unit vector = -0.60 - 0.80 . What is the potential energy of the loop? A) -4.5 × 10<sup>-3</sup> J B) +2.0 × 10<sup>-3</sup> J C) -2.0 × 10<sup>-3</sup> J D) -2.3 × 10<sup>-3</sup> J E) +4.5 × 10<sup>-3</sup> J . The normal to the loop is parallel to the unit vector Potential energy of a current loop: A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field = 0.20 T + 0.40 T . The normal to the loop is parallel to the unit vector = -0.60 - 0.80 . What is the potential energy of the loop? A) -4.5 × 10<sup>-3</sup> J B) +2.0 × 10<sup>-3</sup> J C) -2.0 × 10<sup>-3</sup> J D) -2.3 × 10<sup>-3</sup> J E) +4.5 × 10<sup>-3</sup> J = -0.60 Potential energy of a current loop: A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field = 0.20 T + 0.40 T . The normal to the loop is parallel to the unit vector = -0.60 - 0.80 . What is the potential energy of the loop? A) -4.5 × 10<sup>-3</sup> J B) +2.0 × 10<sup>-3</sup> J C) -2.0 × 10<sup>-3</sup> J D) -2.3 × 10<sup>-3</sup> J E) +4.5 × 10<sup>-3</sup> J - 0.80 Potential energy of a current loop: A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field = 0.20 T + 0.40 T . The normal to the loop is parallel to the unit vector = -0.60 - 0.80 . What is the potential energy of the loop? A) -4.5 × 10<sup>-3</sup> J B) +2.0 × 10<sup>-3</sup> J C) -2.0 × 10<sup>-3</sup> J D) -2.3 × 10<sup>-3</sup> J E) +4.5 × 10<sup>-3</sup> J . What is the potential energy of the loop?


A) -4.5 × 10-3 J
B) +2.0 × 10-3 J
C) -2.0 × 10-3 J
D) -2.3 × 10-3 J
E) +4.5 × 10-3 J

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Q16: Field due to a long wire: Two

Q17: Force on currents: A wire segment 1.2

Q18: Ampere's law: A type of transmission line

Q19: Force on moving charges: Three particles travel

Q20: Field of a circular loop: A long

Q22: Force on currents: A vertical wire carries

Q23: Direction of magnetic fields: A horizontal wire

Q24: Force on parallel wires: A long straight

Q25: Force on parallel wires: As shown in

Q26: Force on currents: A wire along the