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Potential Due to Point-Charges: Two +6

Question 21

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Potential due to point-charges: Two +6.0-μC point charges are placed at the corners of the base of an equilateral triangle, as shown in the figure. (k = 1/4πε0 = 8.99 × 109 N ∙ m2/C2) At the vertex, P, of the triangle Potential due to point-charges: Two +6.0-μC point charges are placed at the corners of the base of an equilateral triangle, as shown in the figure. (k = 1/4πε<sub>0</sub> = 8.99 × 10<sup>9</sup> N ∙ m<sup>2</sup>/C<sup>2</sup>) At the vertex, P, of the triangle (a) what is the electric potential (relative to infinity) due to these charges? (b) what is the magnitude of the electric field due to these charges? (a) what is the electric potential (relative to infinity) due to these charges?
(b) what is the magnitude of the electric field due to these charges?

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(a) 54 kV ...

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