Solved

Charge in an Electric Field: a Proton Is Placed in an Electric

Question 45

Multiple Choice

Charge in an electric field: A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this proton due to this field? (mproton = 1.67 × 10-27 kg, e = 1.60 × 10-19C)


A) 6.71 × Charge in an electric field: A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this proton due to this field? (m<sub>proton</sub> = 1.67 × 10<sup>-27</sup> kg, e = 1.60 × 10<sup>-19</sup>C)  A)  6.71 ×   m/   opposite to the electric field B)  6.71 ×   m/   opposite to the electric field C)  6.71 ×   m/   in the direction of the electric field D)  67.1 ×   m/   opposite to the electric field m/
Charge in an electric field: A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this proton due to this field? (m<sub>proton</sub> = 1.67 × 10<sup>-27</sup> kg, e = 1.60 × 10<sup>-19</sup>C)  A)  6.71 ×   m/   opposite to the electric field B)  6.71 ×   m/   opposite to the electric field C)  6.71 ×   m/   in the direction of the electric field D)  67.1 ×   m/   opposite to the electric field opposite to the electric field
B) 6.71 × Charge in an electric field: A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this proton due to this field? (m<sub>proton</sub> = 1.67 × 10<sup>-27</sup> kg, e = 1.60 × 10<sup>-19</sup>C)  A)  6.71 ×   m/   opposite to the electric field B)  6.71 ×   m/   opposite to the electric field C)  6.71 ×   m/   in the direction of the electric field D)  67.1 ×   m/   opposite to the electric field m/
Charge in an electric field: A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this proton due to this field? (m<sub>proton</sub> = 1.67 × 10<sup>-27</sup> kg, e = 1.60 × 10<sup>-19</sup>C)  A)  6.71 ×   m/   opposite to the electric field B)  6.71 ×   m/   opposite to the electric field C)  6.71 ×   m/   in the direction of the electric field D)  67.1 ×   m/   opposite to the electric field opposite to the electric field
C) 6.71 × Charge in an electric field: A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this proton due to this field? (m<sub>proton</sub> = 1.67 × 10<sup>-27</sup> kg, e = 1.60 × 10<sup>-19</sup>C)  A)  6.71 ×   m/   opposite to the electric field B)  6.71 ×   m/   opposite to the electric field C)  6.71 ×   m/   in the direction of the electric field D)  67.1 ×   m/   opposite to the electric field m/
Charge in an electric field: A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this proton due to this field? (m<sub>proton</sub> = 1.67 × 10<sup>-27</sup> kg, e = 1.60 × 10<sup>-19</sup>C)  A)  6.71 ×   m/   opposite to the electric field B)  6.71 ×   m/   opposite to the electric field C)  6.71 ×   m/   in the direction of the electric field D)  67.1 ×   m/   opposite to the electric field in the direction of the electric field
D) 67.1 × Charge in an electric field: A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this proton due to this field? (m<sub>proton</sub> = 1.67 × 10<sup>-27</sup> kg, e = 1.60 × 10<sup>-19</sup>C)  A)  6.71 ×   m/   opposite to the electric field B)  6.71 ×   m/   opposite to the electric field C)  6.71 ×   m/   in the direction of the electric field D)  67.1 ×   m/   opposite to the electric field m/
Charge in an electric field: A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this proton due to this field? (m<sub>proton</sub> = 1.67 × 10<sup>-27</sup> kg, e = 1.60 × 10<sup>-19</sup>C)  A)  6.71 ×   m/   opposite to the electric field B)  6.71 ×   m/   opposite to the electric field C)  6.71 ×   m/   in the direction of the electric field D)  67.1 ×   m/   opposite to the electric field opposite to the electric field

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions