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Solve the Problem y=30497x+930,140497y = \frac { 30 } { 497 } x + \frac { 930,140 } { 497 }

Question 86

Multiple Choice

Solve the problem.
-Assume that the situation described can be modeled by a straight line graph. Use the given information to find the y = mx + b form of the equation of the line. The number of births in County A has been increasing in recent
Years. Use the information given on the bar graph for the years 1960 and 1990. Let x = 0 represent the year 1960
And y represent the number of births.  Solve the problem. -Assume that the situation described can be modeled by a straight line graph. Use the given information to find the y = mx + b form of the equation of the line. The number of births in County A has been increasing in recent Years. Use the information given on the bar graph for the years 1960 and 1990. Let x = 0 represent the year 1960 And y represent the number of births.   A)   y = \frac { 30 } { 497 } x + \frac { 930,140 } { 497 }  B)   y = \frac { 1990 } { 497 } x - 2190  C)   y = \frac { 497 } { 1990 } x + 1693  D)   y = \frac { 497 } { 30 } x + 1693


A) y=30497x+930,140497y = \frac { 30 } { 497 } x + \frac { 930,140 } { 497 }
B) y=1990497x2190y = \frac { 1990 } { 497 } x - 2190
C) y=4971990x+1693y = \frac { 497 } { 1990 } x + 1693
D) y=49730x+1693y = \frac { 497 } { 30 } x + 1693

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