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Graph the Ellipse $\frac{(x+2)^{2}}{16}+\frac{(y-3)^{2}}{4}=1$ A)

B)

C)

D)

Question 62

Multiple Choice

Graph the ellipse.
- $\frac{(x+2) ^{2}}{16}+\frac{(y-3) ^{2}}{4}=1$
$Graph the ellipse. - \frac{(x+2) ^{2}}{16}+\frac{(y-3) ^{2}}{4}=1 A) B) C) D)$

A)
$Graph the ellipse. - \frac{(x+2) ^{2}}{16}+\frac{(y-3) ^{2}}{4}=1 A) B) C) D)$
B)
$Graph the ellipse. - \frac{(x+2) ^{2}}{16}+\frac{(y-3) ^{2}}{4}=1 A) B) C) D)$
C)
$Graph the ellipse. - \frac{(x+2) ^{2}}{16}+\frac{(y-3) ^{2}}{4}=1 A) B) C) D)$
D)
$Graph the ellipse. - \frac{(x+2) ^{2}}{16}+\frac{(y-3) ^{2}}{4}=1 A) B) C) D)$

Graph the Ellipse (x+2)216+(y−3)24=1\frac{(x+2)^{2}}{16}+\frac{(y-3)^{2}}{4}=116(x+2)2​+4(y−3)2​=1 A) B) C) D)

Multiple Choice

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Graph the Ellipse $\frac{(x+2)^{2}}{16}+\frac{(y-3)^{2}}{4}=1$ A)

B)

C)

D)

Correct Answer:
Verified
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