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    Precalculus Graphical Numerical Algebraic
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    Exam 8: Analytic Geometry in Two and Three Dimensions
  5. Question
    Graph the Hyperbola\[\frac { ( y + 2 ) ^ { 2 } } { 64 } - \frac { ( x + 1 ) ^ { 2 } } { 9 } = 1\]
Solved

Graph the Hyperbola (y+2)264−(x+1)29=1\frac { ( y + 2 ) ^ { 2 } } { 64 } - \frac { ( x + 1 ) ^ { 2 } } { 9 } = 164(y+2)2​−9(x+1)2​=1

Question 134

Question 134

Multiple Choice

Graph the hyperbola.
- (y+2) 264−(x+1) 29=1\frac { ( y + 2 ) ^ { 2 } } { 64 } - \frac { ( x + 1 ) ^ { 2 } } { 9 } = 164(y+2) 2​−9(x+1) 2​=1
 Graph the hyperbola. - \frac { ( y + 2 )  ^ { 2 } } { 64 } - \frac { ( x + 1 )  ^ { 2 } } { 9 } = 1    A)    B)    C)    D)


A)
 Graph the hyperbola. - \frac { ( y + 2 )  ^ { 2 } } { 64 } - \frac { ( x + 1 )  ^ { 2 } } { 9 } = 1    A)    B)    C)    D)
B)
 Graph the hyperbola. - \frac { ( y + 2 )  ^ { 2 } } { 64 } - \frac { ( x + 1 )  ^ { 2 } } { 9 } = 1    A)    B)    C)    D)
C)
 Graph the hyperbola. - \frac { ( y + 2 )  ^ { 2 } } { 64 } - \frac { ( x + 1 )  ^ { 2 } } { 9 } = 1    A)    B)    C)    D)
D)
 Graph the hyperbola. - \frac { ( y + 2 )  ^ { 2 } } { 64 } - \frac { ( x + 1 )  ^ { 2 } } { 9 } = 1    A)    B)    C)    D)

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