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Determine the Eccentricity, the Type of Conic, and the Directrix r=52+8sinθr = \frac { 5 } { 2 + 8 \sin \theta }

Question 103

Multiple Choice

Determine the eccentricity, the type of conic, and the directrix.
- r=52+8sinθr = \frac { 5 } { 2 + 8 \sin \theta }


A) Eccentricity =85= \frac { 8 } { 5 } ; ellipse; directrix y=20y = - 20
B) Eccentricity =4= 4 ; ellipse; directrix y=54y = - \frac { 5 } { 4 }
C) Eccentricity =4= 4 ; hyperbola; directrix y=58y = \frac { 5 } { 8 }
D) Eccentricity =14;= \frac { 1 } { 4 } ; ellipse; directrix y=20\mathrm { y } = - 20

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