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    Precalculus Graphical Numerical Algebraic
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    Exam 5: Analytic Trigonometry
  5. Question
    Prove the Identity\[\frac { \cot x } { 1 + \csc x } = \frac { \csc x - 1 } { \cot x }\]
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Prove the Identity cot⁡x1+csc⁡x=csc⁡x−1cot⁡x\frac { \cot x } { 1 + \csc x } = \frac { \csc x - 1 } { \cot x }1+cscxcotx​=cotxcscx−1​

Question 124

Question 124

Essay

Prove the identity.
- cot⁡x1+csc⁡x=csc⁡x−1cot⁡x\frac { \cot x } { 1 + \csc x } = \frac { \csc x - 1 } { \cot x }1+cscxcotx​=cotxcscx−1​

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