Solved

Find All Solutions to the Equation in the Interval [0 cosx=sin2x\cos x = \sin 2 x

Question 28

Multiple Choice

Find all solutions to the equation in the interval [0, 2) .
- cosx=sin2x\cos x = \sin 2 x


A) 0,π0 , \pi
B) π2,3π2\frac { \pi } { 2 } , \frac { 3 \pi } { 2 }
C) π6,π2,5π6,3π2\frac { \pi } { 6 } , \frac { \pi } { 2 } , \frac { 5 \pi } { 6 } , \frac { 3 \pi } { 2 }
D) 0,π6,5π6,π0 , \frac { \pi } { 6 } , \frac { 5 \pi } { 6 } , \pi

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions