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Find All Solutions to the Equation in the Interval [0 sin2x=sinx\sin 2 x = - \sin x

Question 159

Multiple Choice

Find all solutions to the equation in the interval [0, 2) .
- sin2x=sinx\sin 2 x = - \sin x


A) π4,3π4,5π4,7π4\frac { \pi } { 4 } , \frac { 3 \pi } { 4 } , \frac { 5 \pi } { 4 } , \frac { 7 \pi } { 4 }
B) 0,2π3,π,4π30 , \frac { 2 \pi } { 3 } , \pi , \frac { 4 \pi } { 3 }
C) π8,9π8\frac { \pi } { 8 } , \frac { 9 \pi } { 8 }
D) No solution

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