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Find All Solutions in the Interval [0, 2π) sin2(x2)=sin2x\sin ^ { 2 } \left( \frac { x } { 2 } \right) = \sin ^ { 2 } x

Question 46

Multiple Choice

Find all solutions in the interval [0, 2π) .
- sin2(x2) =sin2x\sin ^ { 2 } \left( \frac { x } { 2 } \right) = \sin ^ { 2 } x


A) 2π3,4π3\frac { 2 \pi } { 3 } , \frac { 4 \pi } { 3 }
B) 0,π0 , \pi
C) 0,2π30 , \frac { 2 \pi } { 3 }
D) 0,2π3,4π30 , \frac { 2 \pi } { 3 } , \frac { 4 \pi } { 3 }

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