Solve the Problem $= 2 \pi \sqrt { 4.57142857 }$ Sec, Frequency

Multiple Choice

Solve the problem.
-Determine the period and frequency of oscillation when a pendulum of length 7 feet is released after being displaced 2 radians.

A) Period $= 2 \pi \sqrt { 4.57142857 }$ sec, frequency $= \frac { 1 } { 2 \pi } \sqrt { 0.21875 }$ cycles per sec
B) Period $= 7 \pi \sec$ , frequency $= \frac { 1 } { 7 \pi }$ cycles per sec
C) Period $= 2 \pi \sqrt { 0.21875 } \mathrm { sec }$ , frequency $= \frac { 1 } { 2 \pi } \sqrt { 4.57142857 }$ cycles per sec
D) Period $= \frac { \pi } { 7 } \mathrm { sec }$ , frequency $= \frac { 7 } { \pi }$ cycles per sec