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Solve the Problem 2ft2 \mathrm { ft } And Released s=12sin114t\mathrm { s } = \frac { 1 } { 2 } \sin \sqrt { \frac { 1 } { 14 } } \mathrm { t }

Question 260

Multiple Choice

Solve the problem.
-A spring with a spring constant of 7 and a 1-unit mass attached to it is stretched 2ft2 \mathrm { ft } and released. What is the equation for the resulting oscillatory motion?


A) s=12sin114t\mathrm { s } = \frac { 1 } { 2 } \sin \sqrt { \frac { 1 } { 14 } } \mathrm { t }
B) s=2sin17ts = 2 \sin \sqrt { \frac { 1 } { 7 } } t
C) s=2sin7ts = 2 \sin \sqrt { 7 } t
D) s=7sin2ts = 7 \sin \sqrt { 2 } t

Correct Answer:

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