Solve the Problem $78 \mathrm {~m}$ If the Width Were Doubled and the Length Were

Multiple Choice

Solve the problem.
-The perimeter of a rectangle is $78 \mathrm {~m}$ . If the width were doubled and the length were increased by $16 \mathrm {~m}$ , the perimeter would be $138 \mathrm {~m}$ . What are the length and width of the rectangle?

A) width $19 \mathrm {~m}$ , length $19 \mathrm {~m}$
B) width $14 \mathrm {~m}$ , length $19 \mathrm {~m}$
C) width $25 \mathrm {~m}$ , length $14 \mathrm {~m}$
D) width $14 \mathrm {~m}$ , length $25 \mathrm {~m}$