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Solve the Problem F(t)=5(t10)21920(t10)210(t10)+16F ( t ) = \frac { 5 ( t - 10 ) ^ { 2 } - 19 } { 20 ( t - 10 ) ^ { 2 } - 10 ( t - 10 ) + 16 }

Question 299

Multiple Choice

Solve the problem.
-A plane suddenly experiences turbulence while in flight. At this point the change in its altitude, in feet, is represt the following function of time:
F(t) =5(t10) 21920(t10) 210(t10) +16F ( t ) = \frac { 5 ( t - 10 ) ^ { 2 } - 19 } { 20 ( t - 10 ) ^ { 2 } - 10 ( t - 10 ) + 16 }
Assuming that the turbulence first hits at time t=0t = 0 , what is the maximum relative drop the plane will experienc due to turbulence? (Round the result to the nearest hundredth.)


A) 0.25ft0.25 \mathrm { ft } .
B) 28.19ft28.19 \mathrm { ft } .
C) 1.27ft1.27 \mathrm { ft } .
D) 10.21ft10.21 \mathrm { ft } .

Correct Answer:

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