Determine the X Values That Cause the Polynomial Function to Be

Multiple Choice

Determine the x values that cause the polynomial function to be (a) zero, (b) positive, and (c) negative.
- $$f ( x ) = ( x + 2 ) ( x + 1 ) ( x - 2 )$$

A) (a) $\{ 2,1 , - 2 \}$ , (b) $( - 2 , - 1 ) \cup ( 2 , \infty )$ , (c) $( * , - 2 ) \cup ( - 1,2 )$
B) (a) $\{ - 2 , - 1,2 \}$ , (b) $( - 2 , - 1 ) \cup ( 2 , \infty )$ , (c) $( \infty , - 2 ) \cup ( - 1,2 )$
C) (a) $\{ - 2 , - 1,2 \}$ , (b) $( \infty , - 2 ) \cup ( - 1,2 \}$ , (c) $( - 2 , - 1 ) \cup ( 2 , \infty )$
D) (a) $\{ - 2 , - 1,2 \}$ , (b) $( - 2,2 )$ , (c) $( \infty , - 2 ) \cup ( 2 , \infty )$