Determine the X Values That Cause the Polynomial Function to Be

Multiple Choice

Determine the x values that cause the polynomial function to be (a) zero, (b) positive, and (c) negative.
- $$f ( x ) = ( x + 7 ) ( x + 5 ) ( x - 7 ) ^ { 2 }$$

A) (a) $\{ - 7 , - 5,7 \}$ , (b) $( \infty , - 7 ) \cup ( - 5 , \infty )$ , (c) $( - 7 , - 5 )$
B) (a) $\{ - 7 , - 5,7 \}$ , (b) $( \infty , - 7 ) \cup ( - 5,7 )$ , (c) $( - 7 , - 5 ) \cup ( 7 , \infty )$
C) (a) $\{ - 7 , - 5,7 \}$ , (b) $( - 7 , - 5 )$ , (c) $( \infty , - 7 ) \cup ( - 5 , \infty )$
D) (a) $\{ - 7 , - 5,7 \}$ , (b) $( \infty , - 7 ) \cup ( 7 , \infty )$ , (c) $( - 7,7 )$