Determine the X Values That Cause the Function to Be $$f ( x ) = \frac { ( x - 2 ) } { ( 2 x + 1 ) ( x - 3 ) }$$

Multiple Choice

Determine the x values that cause the function to be (a) zero, (b) undefined, (c) positive, and (d) negative.
- $$f ( x ) = \frac { ( x - 2 ) } { ( 2 x + 1 ) ( x - 3 ) }$$

A) (a) $\left\{2,3,-\frac{1}{2}\right\}$ (b) $\varnothing$ , (c) $\left(-\infty,-\frac{1}{2}\right) \cup(2,3)$ , (d) $\left(-\frac{1}{2}, 2\right) \cup(3, \infty)$
B) (a) $\{3\}$ , (b) $\left\{3,-\frac{1}{2}\right\}$ , (c) $\left(-\infty,-\frac{1}{2}\right) \cup(2,3) ,(\mathrm{d}) \left(-\frac{1}{2}, 2\right) \cup(3, \infty)$
C) (a) $\{2,3\}$ , (b) $\left\{-\frac{1}{2}\right\}$ (c) $\left\{-\frac{1}{2}, 2\right) \cup(3, \infty) ,(\mathrm{d}) \left(-\infty,-\frac{1}{2}\right) \cup(2,3)$
D) (a) $\{2\}$ , (b) $\left\{3,-\frac{1}{2}\right\}$ , (c) $\left\{-\frac{1}{2}, 2\right) \cup(3, \infty) ,(d) \left(-\infty,-\frac{1}{2}\right) \cup(2,3)$