Multiple Choice
A deuteron is accelerated from rest through a 10-kV potential difference and then moves perpendicularly to a uniform magnetic field with B = 1.6 T.What is the radius of the resulting circular path? (deuteron: m = 3.3 *10-27 kg, q = 1.6*10-19 C)
A) 19 mm
B) 13 mm
C) 20 mm
D) 10 mm
E) 9.0 mm
Correct Answer:

Verified
Correct Answer:
Verified
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