Multiple Choice
A 0.16 pF parallel-plate capacitor is charged to 10 V.Then the battery is disconnected from the capacitor.When 1.00 * 107 electrons are now placed on the negative plate of the capacitor, the voltage between the plates changes by:
A) (-5.0 V.)
B) (-1.1 V.)
C) 0 V.
D) +1.1 V.
E) +5.0 V.
Correct Answer:

Verified
Correct Answer:
Verified
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