Knowing That $g=9.80 \frac{\mathrm{~m}}{\mathrm{~s}^{2}}$ At Sea Level and That RE = 6

Multiple Choice

Knowing that $g=9.80 \frac{\mathrm{~m}}{\mathrm{~s}^{2}}$ at sea level and that RE = 6.37 * 106 m, we find that the value of g in $\frac{\mathrm{m}}{\mathrm{~s}^{2}}$ at a distance RE from the surface of the Earth is:

A) 1.23.
B) 2.45.
C) 4.90.
D) 7.35.
E) 9.80.