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The Height of an Object T Seconds After It Is s(t)=4.9t2+550s ( t ) = - 4.9 t ^ { 2 } + 550

Question 59

Multiple Choice

The height of an object t seconds after it is dropped from a height of 550 meters is s(t) =4.9t2+550s ( t ) = - 4.9 t ^ { 2 } + 550 . Find the average velocity of the object during the first 7 seconds.


A) 34.30 m/sec\quad 34.30 \mathrm {~m} / \mathrm { sec }
B) 34.30 m/sec- 34.30 \mathrm {~m} / \mathrm { sec }
C) 49.00 m/sec- 49.00 \mathrm {~m} / \mathrm { sec }
D) 49 m/sec49 \mathrm {~m} / \mathrm { sec }
E) 16.00 m/sec- 16.00 \mathrm {~m} / \mathrm { sec }

Correct Answer:

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