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The Height Above the Ground of an Object Thrown Upward f(t)=16t2+v0t+s0f ( t ) = - 16 t ^ { 2 } + v _ { 0 } t + s _ { 0 }

Question 155

Multiple Choice

The height above the ground of an object thrown upward from a point feet above the ground with an initial velocity of feet per second is given by the function f(t) =16t2+v0t+s0f ( t ) = - 16 t ^ { 2 } + v _ { 0 } t + s _ { 0 } . A balloon, rising vertically with a velocity of 24 feet per second, releases a sandbag at the instant it is 20 feet above the ground. At what velocity will it hit the ground? Round your answer to three decimal places.


A) 60.111ft/sec- 60.111 \mathrm { ft } / \mathrm { sec }
B) 43.081ft/sec- 43.081 \mathrm { ft } / \mathrm { sec }
C) 15.028ft/sec- 15.028 \mathrm { ft } / \mathrm { sec }
D) 49.298ft/sec49.298 \mathrm { ft } / \mathrm { sec }
E) 67.081ft/sec67.081 \mathrm { ft } / \mathrm { sec }

Correct Answer:

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