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Solve the Differential Equation dfdz=4z+7(2z2+7z+2)2\frac { d f } { d z } = \frac { 4 z + 7 } { \left( 2 z ^ { 2 } + 7 z + 2 \right) ^ { 2 } }

Question 124

Multiple Choice

Solve the differential equation. dfdz=4z+7(2z2+7z+2) 2\frac { d f } { d z } = \frac { 4 z + 7 } { \left( 2 z ^ { 2 } + 7 z + 2 \right) ^ { 2 } }


A) f(z) =2z+7(2z2+7z+2) +Cf ( z ) = \frac { 2 z + 7 } { \left( 2 z ^ { 2 } + 7 z + 2 \right) } + C
B) f(z) =2(2z2+7z+2) +Cf ( z ) = \frac { 2 } { \left( 2 z ^ { 2 } + 7 z + 2 \right) } + C
C) f(z) =7(2z2+7z+2) +Cf ( z ) = \frac { 7 } { \left( 2 z ^ { 2 } + 7 z + 2 \right) } + C
D) f(z) =1(2z2+7z+2) +Cf ( z ) = \frac { - 1 } { \left( 2 z ^ { 2 } + 7 z + 2 \right) } + C
E) f(z) =1(2z2+7z+2) +Cf ( z ) = \frac { 1 } { \left( 2 z ^ { 2 } + 7 z + 2 \right) } + C

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