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Match the Logistic Equation and Initial Condition with the Graph $\frac { d y } { d t } = 2 y \left( 1 - \frac { y } { 14 } \right) , y ( 0 ) = 18$

Question 18

Multiple Choice

Match the logistic equation and initial condition with the graph of the solution. $\frac { d y } { d t } = 2 y \left( 1 - \frac { y } { 14 } \right) , y ( 0 ) = 18$

A)
$Match the logistic equation and initial condition with the graph of the solution. \frac { d y } { d t } = 2 y \left( 1 - \frac { y } { 14 } \right) , y ( 0 ) = 18 A) B) C) D) E)$
B)
$Match the logistic equation and initial condition with the graph of the solution. \frac { d y } { d t } = 2 y \left( 1 - \frac { y } { 14 } \right) , y ( 0 ) = 18 A) B) C) D) E)$
C)
$Match the logistic equation and initial condition with the graph of the solution. \frac { d y } { d t } = 2 y \left( 1 - \frac { y } { 14 } \right) , y ( 0 ) = 18 A) B) C) D) E)$
D)
$Match the logistic equation and initial condition with the graph of the solution. \frac { d y } { d t } = 2 y \left( 1 - \frac { y } { 14 } \right) , y ( 0 ) = 18 A) B) C) D) E)$
E)
$Match the logistic equation and initial condition with the graph of the solution. \frac { d y } { d t } = 2 y \left( 1 - \frac { y } { 14 } \right) , y ( 0 ) = 18 A) B) C) D) E)$

Match the Logistic Equation and Initial Condition with the Graph dydt=2y(1−y14),y(0)=18\frac { d y } { d t } = 2 y \left( 1 - \frac { y } { 14 } \right) , y ( 0 ) = 18dtdy​=2y(1−14y​),y(0)=18

Multiple Choice

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Match the Logistic Equation and Initial Condition with the Graph $\frac { d y } { d t } = 2 y \left( 1 - \frac { y } { 14 } \right) , y ( 0 ) = 18$

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