Solved

Neglecting Air Resistance and the Weight of the Propellant, Determine 5.07×1010ftlb5.07 \times 10 ^ { 10 } \mathrm { ft } - \mathrm { lb }

Question 25

Multiple Choice

Neglecting air resistance and the weight of the propellant, determine the work done in propelling a six-ton satellite to a height of 200 miles above earth. Assume that Earth has a radius of 4000 miles.


A) 5.07×1010ftlb5.07 \times 10 ^ { 10 } \mathrm { ft } - \mathrm { lb }
B) 6.03×109ftlb6.03 \times 10 ^ { 9 } \mathrm { ft } - \mathrm { lb }
C) 1.21×1012ftb1.21 \times 10 ^ { 12 } \mathrm { ft } - \mathrm { b }
D) 1.21×1010ftlb1.21 \times 10 ^ { 10 } \mathrm { ft } - \mathrm { lb }
E) 5.07×1012ftlb5.07 \times 10 ^ { 12 } \mathrm { ft } - \mathrm { lb }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions